4c^2+21c+27=0

Solution for 4c^2+21c+27=0 equation:

Simplifying
4c2 + 21c + 27 = 0

Reorder the terms:
27 + 21c + 4c2 = 0

Solving
27 + 21c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + c)(9 + 4c) = 0

Subproblem 1
Set the factor '(3 + c)' equal to zero and attempt to solve:

Simplifying
3 + c = 0

Solving
3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + c = 0 + -3
c = 0 + -3

Combine like terms: 0 + -3 = -3
c = -3

Simplifying
c = -3
Subproblem 2
Set the factor '(9 + 4c)' equal to zero and attempt to solve:

Simplifying
9 + 4c = 0

Solving
9 + 4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 4c = 0 + -9

Combine like terms: 9 + -9 = 0
0 + 4c = 0 + -9
4c = 0 + -9

Combine like terms: 0 + -9 = -9
4c = -9

Divide each side by '4'.
c = -2.25

Simplifying
c = -2.25
Solution
c = {-3, -2.25}